... Using D = 10 (m-M+5)/5 ,where m=4.3, M=-8.8, that means a high estimate for the nova?s distance from Earth (D) is about 4170 ... Assuming M to be -8.8. The absolute magnitude can be as low as -7.5 for this type. (at least according to Wikipedia) . ...
... Using D = 10 (m-M+5)/5 ,where m=4.3, M=-8.8, that means a high estimate for the nova?s distance from Earth (D) is about 4170 ... Assuming M to be -8.8. The absolute magnitude can be as low as -7.5 for this type. (at least according to Wikipedia) . ...
... Using D = 10 (m-M+5)/5 ,where m=4.3, M=-8.8, that means a high estimate for the nova?s distance from Earth (D) is about 4170 ... Assuming M to be -8.8. The absolute magnitude can be as low as -7.5 for this type. (at least according to Wikipedia) . ...
... If the acceleration could be maintained at roughly 9.8m/sІ (1g or the gravitational acceleration near the Earth's surface), the crew would be able to comfortably walk on their vessel's decks as though it were sitting on the Earth's surface. ...
[
Текст
]
Ссылки http://www.armaghplanet.com/pdf/Astronotes/Astronotes2008/Astronotes_Jan_2008.pdf -- 1141.3 Кб -- 20.09.2011 Похожие документы
... Been reading up a bit on this and major flaw in your reasoning seems to me the asumption you would need to shed the 7-8m/s lateral velocity you need to stay in low orbit. ...
... Been reading up a bit on this and major flaw in your reasoning seems to me the asumption you would need to shed the 7-8m/s lateral velocity you need to stay in low orbit. ...
... Been reading up a bit on this and major flaw in your reasoning seems to me the asumption you would need to shed the 7-8m/s lateral velocity you need to stay in low orbit. ...
... Been reading up a bit on this and major flaw in your reasoning seems to me the asumption you would need to shed the 7-8m/s lateral velocity you need to stay in low orbit. ...