... c) ANU/RSAA 2003 . Discovery of 2003 XB22 on 2003 Dec 15 with the 1.0-m at SSO . ... c) ANU/RSAA 2003 . 2004 CB on 2004 Mar 30, imaged with the 1.0-m at SSO . ... made with the ANU 40 inch (1.0-m) f/8 reflector at Siding Spring Observatory (IAU ...
... 2.41 10 ------ Hz 34 eV eV h 6.62 10 hc hc 6 = ----- = ----- = 1.24 10 ------ eV 1 4 m = 1.24 10 ------ eV 1 19 34 8 1 eV Angstroms Hence the following table (the primary quantity is given in bold): Photon Typical microwave Typical far infrared ...
... Cosmological constant, no photons, and nothing else of interest, the k=-1 solution of the Friedman equations is given by: a M = (cosh 1) a0 2(1M) 1M t= (sinh ) 3/ 2 H 0 2(1M) Problem 3: (3pts) Assuming a matter-dominated Universe (as above) and a value ...
... Out the Equation of State w" p #c 2 "!V #i a 3wi + 3 = constant 3w + 3 $ # '$ a ' & )& ) % # 0 (% a0 ( =1 &M $ & ) # $M ... dt y ln( y ) = H 0 t y=e H0t 2 2 2 ) rad a = = (1 + z ) )M a0 )" ( a =& ) M & a0 ' % # = (1 + z ) # $ !3 !3 · · · N o te th a t ...
... What is its flux at this wavelength: · In f · In f (answers: 4.48в10 -2 0 W m-2 nm-1, 1.16в10 -3 1 W m-2 Hz-1). ... f) flux in V? and in I? What is the ratio between the two? (answers: 1.45в10 -1 9 W m-2 nm-1, 5.91в10 -2 0 W m-2 nm-1, 2.45 ...
... P/2004 CB (LINEAR) . 2004 CB on 2004 Mar 30, imaged with the 1.0-m at SSO . ... During routine astrometry with the 1.0-m to improve the orbit of the Apollo asteroid ... Discoveries . Follow-up Astrometry with the 1.0-m at SSO . Previous News Items . ...
... for my research Atmospheric Transmission optical gamma rays, X-rays & ultravio let infrared radio Atmospheric Opacity 100 % 50 % 0% 1 nm 1m1 mm 1m 1 km Wavelength Frequency Hydrogen Gas in the Universe Hydrogen Gas in the Universe Hydrogen 76% by mass ...
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... tracks predict that all stars with masses in the range 1.4-8 M Sun should become PNe ... of the PN is typically of order 0.1M Sun , and the derived mass is found to depend ...
... 2 2 mJy arcsec mJy arcsec 2 W m1 -------- ----------- 180 3600 I used the plotted ... 12 N m 2 10 7 10 1 1m 3 p tot,min T 3 = 7.2 10 ... this energy is given by E where we take 0.1 Thus, M acc,min min = M acc,min c 2 5 10 ...
... is hc 6.62 10 3.0 10 = ----- = ---------------------------------------------------- = 1.24 10 19 1.60 10 --m 34 8 6 --m1 eV Also, to determine frequency and wavelength given energy, use =h hc = ----1.60 10 = -- = ------------------------- 34 h 6.62 10 hc ...