... H 0 , H 0 ) dQ (& + J ) + I& j=1 S j - t - l 2 Re M = >> 1; M = 0, M G i In the case of Europa l ~ 100 000 m, ~ 50 (Ohm) = 1.62 ... If ReM=. -1m -1, M = 0 ; J ( t ) = -I( t ) ; H = I(t )(H 0 - H 0 ) ; S j I(t )H ( ) = H ; (H, ) = 0 ; j = 1, 2. ...
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Ссылки http://www.cosmos.ru/conf/2009elw/presentations/presentations_pdf/session4/rabinovich_ELW.pdf -- 292.3 Кб -- 02.03.2009 Похожие документы
... 0 -1 -2 -3 -4 -2 0 U Fo r C-b an d 1m/s su rface cu rren t co rres po nds to Do p p ... 5 25 -1 ] m k [ 20 -1 . 5 15 -2 10 -2 . ... Jet w idth is 80 km, V eloc ity is 1.5 m/s ; Sw ell: KA =0.05, L=200 m Radar obs er ...
... So: m1 = 1500 kg v 1 = 40 km/s . m 2 = 4500 kg v 2 = -20 km/s . Let v 3 be the final velocity of the wreckage. ... P = m1 v 1 + m 2 v 2 = (m1 + m 2 )v 3 or . 1500*40 + 4500*(-20) = 60,000 - 90,000 = -30,000 = 6000*v . v = - 5 km/s . ...
... E < 15 keV; anisotropy of electrons and ions (M = 1, 4, 16), 30 < E < 500 keV/Q ... Electron and ion spectra and anisotropy (M = 1, 2, 4, 16), 0.005 < E < 20 keV/Q . ... Ion composition (M = 1-32) and 3-D energy distribution, 10 eV < E < 30 keV/Q . ...
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... So: m1 = 1500 kg v 1 = 40 km/s . m 2 = 4500 kg v 2 = -20 km/s . Let v 3 be the final velocity of the wreckage. ... P = m1 v 1 + m 2 v 2 = (m1 + m 2 )v 3 or . 1500*40 + 4500*(-20) = 60,000 - 90,000 = -30,000 = 6000*v . v = - 5 km/s . ...
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