Документ взят из кэша поисковой машины. Адрес оригинального документа : http://nuclphys.sinp.msu.ru/conf/epp10/Zhukovsky.pdf Дата изменения: Sat Sep 7 16:48:01 2013 Дата индексирования: Fri Feb 28 02:47:55 2014 Кодировка:

Planar Undulator Performance and Harmonic Generation in a Constant Magnetic Field
*M.V..Lomonosov Moscow State University, Physical Faculty, dept. of Theoretical Physics. 119992 Moscow, Leninskie Gory. zhukovsk@phys.msu.ru

K.V. Zhukovsky*,





2 0 1 0

2

=
0

0
0

0
2

=

·

­

>> 1,

<< 1,

<<

0


-
2 2 2

:

=

4

2

/

,

.
, =

,;, 2

= 1 2 1 2 1

1 2


,

,;,

=

1
0

,

,;,

=

=

,

,

=

, =

,,,

=

,

,,,

=

1

,

,

,

,



1 0
2 3


1 0
3

0


00

2

2


Fundamental harmonic line of the UR: with an ideal sinusoidal field = 0 -- continuous line; in the presence of the constant field, such that = 4 -- dashed line, = 6 -- dash-dotted line, = 7.5 -- thick dashed line.

|S| 1

2

0.8 0.6 0.4 0.2
n

-30

-20

-10

10

UR line has good shape when

8


0

=
0

2 1

2 0 2

2

=
n

0

2

2

= 012 3




2


1








2
0 2

2 0 2

= 012 3

1

2

2 3

1

1 3

2

1

0

Bd Bd


0 0

1

1

2

2
2

2
n Res

2

2

3

1

2

2

312 1
n Res

2 1 2
3 2 d


0

1

2

3

S(, , ).

, 1
2 2 2 2 2

=
=0

1

2

2

2 2

n 2 2

1

8
n n 2

1 2

8
2

4

2 1

8


(n=2)

0.01 0.0075 0 0.5 1 10
4

0.005 0.0025 0 0
n

I

1.5 2 2.5 -24 -18 -12 -6

6

12 18

24


1
1 max 32

31 2

1
2

0 0.5 10
4

1 1.5

1824 6 12 2 -6 0 -18 12 n 2.5 -24

1 0.75 0.5 I 0.25 0
n Res

02
0

n Res

2


0 0 0

1

1

2

n

1

2

2

12 312 1

2 1 2

1

<

1
1

0

n


2 2

1

2

2

· x,y -- electron beam angular divergences in the undulator, x,y-- horizontal and the vertical emittances of the beam, x,y -- the beam size. · Is the broadening dominated by the angular divergence of the beam or by the constant magnetic field? It depends on which bending angle is bigger: x,y> H or x,y< H


2
n 0 0 2

2 0 2

1

2

2
1

3


3 2

2 1

2

1

3 2
1

0

3 2
1

2

2
10


n

4

2

2

2
2

2

4
0

14


10

6

0.1 0.5 1

1.5 2 1 0.75 0.5 I 0.25 0

-12 -9 -6 -3 0
n

3

6

9 12

k = 2, N = 100.


N = 150. n = 1, k = 2
1

Bd~810-5B0.I

0.75 0.5 0.25 0 6 3 0.5 1 1.5 10
4

12 9 0 -3 -6 -9 -12 2.5

Bd

max

~10-4B0.

N = 150

5 kGauss Bd~110-4B

Bd.

2

0


0 0.5

N = 150, n = 1, k = 2, = 10-10, off-axis angle: = 0.15

10

4

1

1.5 2 2.3 1 0.75 I 0.5 0.25 0 -24-18-12 -6 0 6 12 18 24
n

Bd ~1.0В1.8 10-4B0. Bd >2 10-4B0


0 0.5

Novosibirsk, Siberia 2:

1 10
4

N = 300, n = 1, k = 0.5, = 10-8, B0 = 7.5kG, offaxis angles: ~ 0.04. Bd~0.7 10-4B0 0.5G. (f Bd >10-4B0

1.5 2 2.3 1 0.75 I 0.5 0.25 0 -24 -18 -12 -6 0
n

6 12 18 24