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... . ... S. Auclair, R. Uzbekov, S. Elis, L. Sanchez, I. Kireev, L. Lardic, R. Dalbies-Tran, and S. Uzbekova. ... I. Vorobjev, K. Buchholz, P. Prabhat, K. Ketman, E. Egan, M. Marti, M. Duraisingh, and N. Barteneva. ... Belmont AS, Hu Y, Sinclair PB, Wu W, Bian Q, Kireev I. Insights into Interphase Large-Scale Chromatin Structure from Analysis of Engineered Chromosome Regions. ... , (2010), . 52, ? ... Hu Y., Kireev I., Plutz M., Ashourian N., Belmont AS. ... 2008), 5(4):311...
The beamer class Manual for version 3.06. \begin{frame} \frametitle{There Is No Largest Prime Number} \framesubtitle{The proof uses \textit{reductio ad absurdum}.} \begin{theorem} There is no largest prime number. \end{theorem} \begin{proof} \begin{enumerate} \item<1-| alert@1> Suppose $p$ were the largest prime number. \item<2-> Let $q$ be the product of the first $p$ numbers. \item<3-> Then $q+1$ is not divisible by any of them. \item<1-> Thus $q+1$ is also prime and greater than $p$.\qedhere
P.P. P . ... T : distS t; Ba ; M ; t; Ba ; t 0: T 6 , M M Ba : .R " S T; Ba : W " Ba | ... 1 kS0 T; u , S0 T; vk Lku , vk; kS0 T; u , S T; uk " 8u; v 2 Ba : T 0 ;"1 ;Ba , . ... 2 " Ba2 " B1 = S T; Ba2 S ;S0 "2 "+L"2 B1 1; 2. ... h 2Oi , distS n h; M i n; S k h 2Oi ; O i N. Oi zi O, 1 i n M i N, 3 0kn : jOi j S . distzi ; Oj jOi jL2 ; Oi , L V V S h i 6= j; N i O0 = On O i=0 0 n= Ln distS n h; M. : h 0 0 v V h V; \ n 2O; 4 0 qV h; q 1; 8h 2O : distS n0 +n h0 ; M max fjOj;Ln0 g n=N +1 6 T 10 . ...