... a) int x = 0; int f ( int a, int b) { return x = a + b; } class A { int x; public : A ( int n = 1) { x = n; } int f() { return ::x = x; } }; class B { int x; public : B ( int n = 2) { x = n; } }; class C: public A, public B { int x; public : int f( int a) { return ::x = x; } void g (); }; ... class X { public: void g () {cout << "g" << endl;} int h (int n) {cout << "f" << endl; return n} }; int main () { int k; const X x; X::g(); k = x.h(5); return 0; } 6.3. ...

Еще в разделе: (Показать все результаты (>2) - al.cmc.msu.ru/ )

• http://al.cs.msu.ru/files/formal.languages.translation.theory.pdf

... п?я?я€п°пҐп?я?п° п©пЎпЄпЄп?я€пІп?п? п?я?я€я?п° "п?п?пЕпЎя€п?я?п?я? п? п°п?пЕпЎя€п?я?п?п?я?п?я?п?п?п? я?пЇя?п?п?" пЄп?я? 1 п©пЎя?пЎп?п° . ... 2014 пЕпЎпЄ . ... Older posts . Posted on 15.01.2016 by abel . п? 8.45 18 я?пҐп?п°я€я? пҐп?пЎп?я?пЎпЄп?п?пЎ п©пЎпЄпЎп№я?п? п? я?п?п?пЄя?я?я?п?п? п°я?пЄп?я?пЎя€п?я?п?: пЕя€я?п©п©я? 101, 103 Б€? п? п°я?пЄ. п?-5, пЕя€я?п©п©я? 104, 105 Б€? п? п°я?пЄ. п?-6, пЕя€я?п©п©я? 102, 106 Б€? п? п°я?пЄ. п?-14. п?п?п?п°п?п? я?я?п©п?я?п°! ... Leave a comment . ...

Еще в разделе: (Показать все результаты (>4) - algcourse.cs.msu.su/ )

The beamer class Manual for version 3.06. \begin{frame} \frametitle{There Is No Largest Prime Number} \framesubtitle{The proof uses \textit{reductio ad absurdum}.} \begin{theorem} There is no largest prime number. \end{theorem} \begin{proof} \begin{enumerate} \item<1-| alert@1> Suppose $p$ were the largest prime number. \item<2-> Let $q$ be the product of the first $p$ numbers. \item<3-> Then $q+1$ is not divisible by any of them. \item<1-> Thus $q+1$ is also prime and greater than $p$.\qedhere

284. vartan | Архитектура ЭВМ и язык ассемблера

285. Slide 1